1-cos2x=2sinx Log1/3(1-2x)>-1  

1-cos2x=2sinx 1-cos^2 x+sin^2 x=2sinx 2sin^2 x=2sinx sin^2 x=sinx sin^2 x-sinx=0 sinx(sinx-1)=0 sinx=0 x=pi*k; k пр. Z sinx-1=0 sinx=1 x=pi/2+2pi*k; k пр. Z.   log1/3(1-2x)>-1                      1-2x>0; 2x<1; x<1/2 (ОДЗ) log1/3(1-2x)>log 1/3 3 1-2x<3 2x>-2 x>-1   Ответ: x пр. промежутку (-1;0.5)

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