Взять производную....

(x²-4)`=2x(cosx/2+2sin3x)`=-1/2*sinx/2+6cos3x(3/(x+4))`=-3/(x+4)²(3x/(x+4))`=(3(x+4)-3x*1)/(x+4)²=(3x+12-3x)/(x+4)²=12/(x+4)²[latex](x ^{3/4} -2x ^{3/2} +5)`=3/4*x ^{-1/4} -3x ^{1/2} [/latex]