Помогите с 13 номером

2sin²x=√3sinxsinx(2sinx-√3)=0sinx=0x=πn,n∈z-3π≤πn≤-3π/2-3≤π≤-1,5n=-3⇒x=-3πn=-2⇒x=-2πsinx=√3/2x=π/3+2πk,k∈z-3π≤π/3+2πk≤-3π/2-18≤2+12n≤-9-20≤12n≤-11-4/3≤n≤-11/12n=-1⇒x=π/3-2π=-5π/3sinx=2π/3+2πm,m∈z-3π≤2π/3+2πm≤-3π/2-18≤2+12m≤-9-20≤12m≤-11-4/3≤m≤-11/12m=-1⇒x=2π/3-2π=-4π/3