Решите уравнение: а)x^2+2=3-x б)5x+2=2-2x^2 в)2x^2+3=3-7x г)x^2-6x=4x-25 д)x^2+2x=16x-49

1) x² + 2 - 3 + x = 0x² + x - 1 = 0D = b² - 4ac = 1 - 4×(-1) = 5x1,2 = ( - 1 + √5) / 22) 5x + 2 - 2 + 2x² = 02x² + 5x = 0x( 2x + 5) = 0x =02x + 5 = 02x =- 5x =- 2,53) 2x² + 3 - 3 + 7x = 02x² + 7x = 0x( 2x + 7) = 0x = 02x+ 7 = 02x = - 7x = - 3,54) x² - 6x - 4x + 25 = 0x² - 10x + 25 = 0D = b² - 4ac = 100 - 4×25 = 0 - имеет один корень.x= - b/2ax = 10/2x = 55) x² + 2x - 16x + 49 = 0x² - 14x + 49 = 0D = b² - 4ac = 196 - 4×49 = 0 - имеет один корень.x =- b/2ax = 14/2x = 7