Решите через дискриминантx^2-7x-18<0-6x^2+13x-5≤0x^2-6x-7=0

1. [latex] x^{2} -7x-18 extless 0 \ \ D=(-7)^2-4*(-18)=121 extgreater 0 \ \ x1= frac{7+11}{2}=9 \ x2= frac{7-11}{2}=-2 [/latex](-2; 9)2.[latex]-6x^2+13x-5 leq 0 \ D=13^2-4*(-6)*(-5)=49 extgreater 0 \ x1= frac{-13+7}{2*(-6)} =0.5 \ x2= frac{-13-7}{2*(-6)}=1 frac{2}{3} [/latex][latex][0.5; 1 frac{2}{3}] [/latex]3.[latex] x^{2} -6x-7=0 \ D=-6^2-4*1*(-7)=64 extgreater 0 \ x1= frac{6+8}{2} =7 \ x2= frac{6-8}{2} =-1 \ [/latex]Ответ: -1, 7