2 и 3 задание зеленое

2.aM(CO2)=12+32=44g/molwC=12/44*100%=27.3%wO=100-27.3=72.7%b)M(CaS)=40+32=72g/molwCa=40/72*100%=55.55%wS=100-55.55=44.45%v)M(NaNO3)=23+14+48=85g/molwNa=23/85*100%=27%wN=14/85*100%=16.5%wO=100-27-16.5=56.5%g) M(Al2O3)=54+48=102g/molwAl=54/102*100%=53%wO=100-53=47%3.a) M(NH4Cl)=14+4+35.5=53.5g/molwN=14/53.5*100%=26%b) M((NH4)2SO4)=28+8+32+64=132g/molwN=28/132*100%=21%v) M((NH2)2CO)=28+4+12+16=60g/molwN=28/60*100%=46.6%ответ: в-46.6%