Решите пожалуйсто,тему нам не объяснили...

1) =(5a-k+k-3a)/ 7k=2a/7k2) =(a²-5a-(3a-10)+6)/3(a²-16)=(a²-5a-3a+10+6)/3(a²-16)=(a²-8a+16)/3(a²-16)    =(a-4)²/3(a-4)(a+4)=(a-4)/3(a+4)3)=a²-8ab+16b²-(a²+8ab+16b²)/ab=(a²-8ab+16b²-a²-8ab-16b²)/ab=   =-16ab/ab= -164) =a(3-2b)/(b(a-5b))+(5b(3-2b))/ -b(a-5b)= (a(3-2b)-5b(3-2b))/b(a-5b)=   =(3-2b)(a-5b)/b(a/5b)=(3-2b)/b b=300   (3-2*300)/300=-597/300=-1  297/300=-1 99/100=-1,995) =(2a-k)/3*11k +(k-3a)/4*11k=(4*(2a-k)+3(k-3a))/11k*3*4=    =(8a-4k+3k-9a)/132k=-a-k/132k