Решите уравнение и неравенство пожалуйста

[latex]sqrt{x^2-2x-4}=sqrt{2x^2-6x-1}, \ left { {{x^2-2x-4geq0,} atop {2x^2-6x-1geq0;}} ight. left { {{D=5, left [ {{xleq1-sqrt{5},} atop {xgeq1+sqrt{5};}} ight. } atop {D=11, left [ {{xleqfrac{3-sqrt{11}}{2},} atop {xgeqfrac{3+sqrt{11}}{2}}} ight. }} ight. left [ {{xleq1-sqrt{5},} atop {xgeq1+sqrt{5};}} ight. \ x^2-2x-4=2x^2-6x-1, \ x^2-4x+3=0, \ x_1=1, x_2=3, \ 1-sqrt{5} extless 1 extless 1+sqrt{5}, \ 1-sqrt{5} extless 3 extless 1+sqrt{5}, \ xinvarnothing.[/latex][latex]log_xfrac{2x+5}{4(x-1)}leq0, \ left { {{frac{2x+5}{4(x-1)} extgreater 0,} atop {4(x-1) eq 0;}} ight. \ (2x+5)(x-1) extgreater 0, \ left [ {{x extless -2,5,} atop {x extgreater 1;}} ight. [/latex][latex]left [ {{ left { {{0 extless x extless 1,} atop {frac{2x+5}{4(x-1)} geq 1,}} ight. } atop {left { {{x extgreater 1,} atop {frac{2x+5}{4(x-1)}leq1,}} ight.}} ight. left [ {{ left { {{0 extless x extless 1,} atop {frac{2x+5}{4(x-1)}-1geq0,}} ight. } atop {left { {{x extgreater 1,} atop {frac{2x+5}{4(x-1)}-1leq0,}} ight.}} ight. left [ {{ left { {{0 extless x extless 1,} atop {frac{-2x+9}{4(x-1)}geq0,}} ight. } atop {left { {{x extgreater 1,} atop {frac{-2x+9}{4(x-1)}leq0,}} ight.}} ight. [/latex][latex] left [ {{ left { {{0 extless x extless 1,} atop {(2x-9)(x-1)leq0,}} ight. } atop {left { {{x extgreater 1,} atop {(2x-9)(x-1)geq0,}} ight.}} ight. left [ {{ left { {{0 extless x extless 1,} atop {1 extless xleq 4,5,}} ight. } atop {left { {{x extgreater 1,} atop { left [ {{x extless 1,} atop {x geq 4,5;}} ight. }} ight.}} ight. left [ {{xinvarnothing,} atop {x geq 4,5; }} ight.}} ight. \ x geq 4,5.[/latex]