Решите срочно уравнение

[latex] frac{y+3}{y-3}- frac{y-3}{y+3}=1.5 \ \ y eq 3 \ y eq -3 [/latex](y+3)² - (y-3)² = 1.5(y-3)(y+3)y² +6y+9 -(y² -6y+9)=1.5(y² -9)y² +6y+9-y² +6y-9=1.5y² -13.5-1.5y² +12y+13.5=0y² - 8y - 9=0D=64+36=100y₁=(8-10)/2= -1y₂=(8+10)/2=9Ответ: -1;  9.

ОЗ (y-3)(y+3)≠0y≠3y≠-3(y+3)²-(y-3)²=1,5(y²-9)(y+3-y+3)(y+3+y-3)=1,5y²-13,512y=1,5y²-13,5y²-8y-9=0y1+y2=8 U y1*y2=-9y1=-1y2=9