Log x^3-9x^2+27x-27(9-x)≥0 нужно подробно!)

[latex] log_{ x^{3} - 9 x^{2} +27x-27}(9 - x) geq 0 \ x^{3} - 9 x^{2} +27x-27 = (x-3)^{3} = extgreater \ log_{ (x-3)^{3}}(9 - x) geq 0 \ frac{1}{3} log_{ (x-3)}(9 - x) geq 0 \ [/latex][latex] log_{ (x-3)}(9 - x) geq 0 \ log_{ (x-3)}(9 - x) - 0 geq 0 \ log_{ (x-3)}(9 - x) - log_{ (x-3)}1 geq 0 \ [/latex][latex] left { {{(x-3 -1)(9-x-1)geq 0 \} atop {x-3 extgreater 0, x-3 eq 1,9 - x extgreater 0} } ight. \ left { {{(x-4)(8-x)geq 0 \} atop {x extgreater 3, x eq 4,x extless 9} } ight. \ left { {{(x-4)(x-8) leq 0 \} atop {x extgreater 3, x eq 4,x extless 9} } ight. \[/latex][latex] left { {{4 leq x leq 8 \} atop {x extgreater 3, x eq 4,x extless 9} } ight. \ 4 extless x leq 8 \ [/latex]Ответ:  ( 4 ; 8 ].