CosΠ√x=-√3/2 Решитеее

Cos (π/2 - t) - Sin (π+t) = √2sint + sint = √22sint = √2sint = √2/2t = (-1)^(n)*arcsin(√2/2) + πn, n∈Zt = (-1)^(n)*(π/4) + πn, n∈Z2)  Sin x/3 = -1/2x = (-1)^(n)*arcsin(-1/2) + πk, n∈Zx/3 = (-1)^(n+1)*arcsin(1/2) + πk, k∈Zx/3 = (-1)^(n+1)*(π/6) + πk, k∈Zx = (-1)^(n+1)*(3π/6) + 3πk, k∈Zx = (-1)^(n+1)*(π/2) + 3πk, k∈Z3)  5 Cos^2 x + 6 Sin x - 6 = 05*(1 - sin^2x) + 6sinx - 6 = 05 - 5*(sin^2x) + 6sinx - 6 = 05*(sin^2x) - 6sinx + 1 = 0D = 36 - 4*5*1 = 16a)  sinx = (6 - 4)/10sinx = 1/5x = (-1)^(n)*arcsin(1/5) + πn, n∈Zб)  sinx = (6 + 4)/10sinx = 1x = π/2 + 2πk, k∈Z я в 4 классе учусь в гимназии