Решите уравнение: (3х+1)²-6х=3

(3х+1)²-6х=3 (a+b)²=a²+2ab+b²(3х+1)²=3²x²+2*3x*1+1²=9x²+6x+19x²+6x+1-6x=39x²+1=39x²=3-19x²=2[latex] x^{2} = frac{2}{9} \ x=pm sqrt{ frac{2}{9}} \ x=pmfrac{ sqrt{ 2}}{ sqrt{ 9} } \ x=pm frac{ sqrt{2} }{3} [/latex]