Решить уравнение 9^x+27=28*3^x

[latex]9^x+27=28*3^x\ 3^{2x}+27-28*3^x=0\ 3^x=t\ left { {{t^2-28t+27=0} atop {t extgreater 0}} ight. \ left { {{t_1=27;t_2=1} atop {t extgreater 0}} ight. \ left { {{3^x=27} atop {3^x=1}} ight. \ left { {{x=3} atop {x=0}} ight. \[/latex]