Решите пожалуйста: 8sin^4x+10sin^x-3=0

Решение8sin⁴x + 10sin²x - 3 = 0sin²x = t, t ≥ 08t² + 10t - 3 = 0D = 100 + 4*8*3 = 196t₁ = (- 10 - 14)/16t₁ = - 24/16t₁ = - 1,5, не удовлетворяет условию  t ≥ 0t₂ = (- 10 + 14)/16t₂ = 4/16t₂ = 1/4sin²x = 1/4sinx = - 1/2sinx = 1/21) sinx = - 1/2x = (-1)^n*arcsin(-1/2) + πn, n∈Zx = (-1)^(n+1)*arcsin(1/2) + πn, n∈Zx = (-1)^(n+1)*arcsin(1/2) + πn, n∈Zx = (-1)^(n+1)*(π/6) + πn, n∈Z2)  sinx = 1/2x = (-1)^k*arcsin(1/2) + πk, n∈Zx = (-1)^k*(π/6) + πk, k∈Z