(x+3)(x-4)=-12 (3x-1)^2=1 (2x+3)(3x+1)=11x+30 18-(x-5)(x-4)=-2 5x+(2x+1)(x-3)=0 x^2-5=(x-5)(2x-1) через дискриминант

Решение1)  (x+3)(x-4)=-12x² - x - 12 = - 12x(x - 1) = 0x₁ = 0x₂ = 1Ответ: х₁ = 0 : х₂ = 12)  (3x-1)^2=13x - 1 = - 1 3x = 0 x₁ = 03x - 1 = 1 3x = 2x₂ =  2/3 Ответ: х₁ = 0; х₂ = 2/33)  (2x+3)(3x+1)=11x+306x² + 11x + 3 = 11x + 306x² = 27x² = 9/2x₁ = - 3√2/2x₂ = 3√2/2Ответ: x₁ = - 3√2/2; x₂ = 3√2/24)  18-(x-5)(x-4)=-2x² - 9x + 20 = 20x(x - 9) = 0x₁ = 0x₂ = 9Ответ: x₁ = 0 ; x₂ = 95)  5x+(2x+1)(x-3)=05x + 2x² - 5x - 3 = 02x² - 3 = 02x² = 3x² = 3/2x₁ = - √6/3x₂ = √6/36)  x^2-5=(x-5)(2x-1)x² - 5 = 2x² - 11x + 5x² - 11x + 10 = 0x₁ = 1x₂ = 10Ответ: x₁ = 1 ; x₂ = 10