Найдите длину векторов a, b, c: a (2;1), b (3;3), с (-4;0)

|а|^2= 4+1=5 |а|=√5 |в|^2=9+9=18 |в|=√18=3√2 |с|^2=16+0=16 |с|=√16=4

a{2;1} ;|a| = [latex] sqrt{2^2+1^2}= sqrt{4+1} = sqrt{5} [/latex]b{3;3} ;|b| = [latex] sqrt{3^2+3^2} = sqrt{9+9} = sqrt{18}= sqrt{3^2*2} =3 sqrt{2} [/latex]c{-4;0} ;|c| = [latex] sqrt{(-4)^2+0^2}= sqrt{16}=4 [/latex]Ответ: [latex] sqrt{5 } ; 3 sqrt{2} ; 4[/latex]