Решите уравнение 3х^2-6x-44=(x-4)^2

3x² - 6x - 44 = ( x - 4)( x- 4)3x² - 6x - 44 = x² - 8x + 163x² - 6x - 44 - x² + 8x - 16 = 02x² + 2x - 60 = 0x² + x - 30 = 0D = b² - 4ac = 1 - 4 × (-30) = 121 = 11²x1 = ( - 1 + 11) / 2 = 5x2 = ( - 1 - 11) / 2 = - 6

[latex]3x^{2} -6x - 44 = (x - 4)^{2}[/latex][latex] 3x^{2} -6x - 44 = x^{2} - 8x + 16[/latex][latex]2 x^{2} + 2x - 60 = 0[/latex][latex] x^{2} + x -30 = 0[/latex][latex] x_{1} = frac{ -1 + sqrt{1 + 120}}{2} x = 5[/latex][latex] x_{2} = frac{ -1 - sqrt{1 + 120}}{2} x = -6[/latex]