СРОЧНО, помогите! (10х-4)(3х+2)=0

(10х-4)(3х+2)=030x^2+20x-12x-8=030x^2+8x-8=0D=8^2-4*30*(-8)=64+960=1024 √D=32x1=-8-32/2*30=-40/60=-2/3x2=-8+32/2*30=24/60=2/5

(10x-4)(3x+2)=030x²+20x-12x-8=030x²+8x-8=0d = b²-4acd = 64 + 960d = 1024[latex]x= frac{-b+- sqrt{d} }{2a} [/latex][latex]x= frac{-8+-32}{60} [/latex][latex] x_{1} = - frac{40}{60} =- frac{20}{30} = -frac{4}{6} = -frac{2}{3} [/latex][latex] x_{2} = frac{24}{60} = frac{4}{10} = frac{2}{5} [/latex]Ответ: [latex](- frac{2}{3}; frac{2}{5} )[/latex]