Решите уравнение [latex] 3^{4x+5}- 2^{4x+7}- 3^{4x+3} - 2^{4x+4}=0 [/latex]

3^(4x+5)-2^(4x+7)-3^(4x+3)-2^(4x+4)=03^(4x+5)-3^(4x+3)=2^(4x+7)+2^(4x+4)(3^(4x+3))*(3²-3⁰)=(2^(4x+4))*(2³+2⁰)(3^(4x+3))*(9-1)=(2^(4x+4))*(8+1)(3^(4x+3))*8=(2^(4x+4))*9 |: 72(3^(4x+3))/9=(2^(4x+4))/83^(4x+3-2)=2^(4x+4-3)3^(4x+1)=2^(4x+1)a^m=b^m, ⇒m=04x+1=0, 4x=-1x=-0,25