Реши уравнение 3ц 16 - (х +1 ц 1 12) = 14 Ц- целых

[latex]3 frac{1}{6} - (x + 1 frac{1}{12}) = frac{1}{4}[/latex][latex]3 frac{1}{6} - x - 1 frac{1}{12} = frac{1}{4}[/latex][latex]- x = frac{1}{4} - 3 frac{1}{6} + 1 frac{1}{12} [/latex][latex]- x = frac{3}{12} - 3 frac{2}{12} + 1 frac{1}{12}[/latex][latex]- x = -1 frac{5}{6} [/latex][latex]x = 1 frac{5}{6} [/latex]