{х^2+у^2=5 {х-у=м Помогите?))

[latex] left { {{x^2+y^2=5,} atop {x-y=m;}} ight. left { {{x^2+(x-m)^2=5,} atop {y=x-m;}} ight. left { {{2x^2-2mx+m^2-5=0,} atop {y=x-m;}} ight. \ D_1=(-m)^2-2cdot(m^2-5)=10-m^2 geq 0, \ m^2-10 leq 0, \ (m+sqrt{10})(m-sqrt{10}) leq 0, \ -sqrt{10} leq m leq sqrt{10}, \ min[-sqrt{10};sqrt{10}]; \ x_{1,2}=frac{mpmsqrt{10-m^2}}{2}; [/latex][latex]left { {{ left [ {{x=frac{m-sqrt{10-m^2}}{2},} atop {x=frac{m+sqrt{10-m^2}}{2};}} ight. } atop {y=x-m;}} ight. left [ {{ left { {{x=frac{m-sqrt{10-m^2}}{2},} atop {y=frac{m-sqrt{10-m^2}}{2}-m;}} ight. } atop {left { {{x=frac{m+sqrt{10-m^2}}{2},} atop {y=frac{m+sqrt{10-m^2}}{2}-m;}} ight. }} ight. [/latex] [latex] left [ {{ left { {{x=frac{m-sqrt{10-m^2}}{2},} atop {y=-frac{m+sqrt{10-m^2}}{2};}} ight. } atop {left { {{x=frac{m+sqrt{10-m^2}}{2},} atop {y=frac{sqrt{10-m^2}-m}{2};}} ight. }} ight.[/latex]