Решите методом подстановки систему 2x^2 - y^2 = 2 3x + 2y = 1

[latex] left { {{2x^2 - y^2 = 2,} atop {3x + 2y = 1;}} ight. left { {{2x^2 - frac{1}{4}(1-3x)^2 = 2,} atop {y = frac{1}{2}(1-3x);}} ight. left { {{8x^2 - (1-6x+9x^2) = 8,} atop {y = frac{1}{2}(1-3x);}} ight. left { {{-x^2+6x-9 = 0,} atop {y = frac{1}{2}(1-3x);}} ight. \ left { {{-(x-3)^2 = 0,} atop {y = frac{1}{2}(1-3x);}} ight. left { {{x-3 = 0,} atop {y = frac{1}{2}(1-3x);}} ight. left { {{x = 3,} atop {y = -4.}} ight. [/latex]