(X+1)(x+2)(x+3)(x+4)=3

Решение(X+1)(x+2)(x+3)(x+4)=3[(X+1)(x+4)]*[(x+2)(x+3)] = 3(x² + 5x + 4)*(x² + 5x + 6) = 3Gecnm x² + 5x + 4 =tt*(t + 2) = 3t² + 2t - 3 = 0t1 = - 3t2 = 1x² + 5x + 4 = - 3x² + 5x + 7 = 0D = 25 - 4*1*7 = - 3 < 0решений нетx² + 5x + 4 = 1x² + 5x + 3 = 0D  = 25 - 4*1*3 = 13x1 = (- 5 -√13) /2 = - √13 / 2 - 2(1/2)x2 = (- 5 + √13) /2 =  √13 / 2 -  2(1/2)