49 ^log(7)4 Log(2)log(5) 8√5 Log(√2)log(1/3) 1/9 Log(12)3+log(12)4 7 ^[2log(7)16] 10[^1-1g5] 4^[3-log(4)64] 6^[2/log(5)6]

49^loq(7)4=(7^2)^loq(7)4=(7^loq(7)4)^2=4^2=16loq(V2)loq(1/3)1/9=loq(V2)2=2loq(2)2=2loq*(12)3+loq(12)4=loq(12)(3*4)=loq(12)12=17^[2loq(7)16]=((7^loq(7)16)^2)=16^2=25610^[1-lq5]=10^1/10^lq5=10/5=24^[3-loq(4)64]=4^3/4^loq(4)64=4^3/4^3=16^[2/loq(5)6]=6^[(loq(5)25)/(loq(5)6)]=6^[loq(6)25)]=25второй примерloq(2)(loq(5)5^(1/8))=loq(2)1/8=loq(2)2^(-3)=-3