Решите систему уравнений (x+y)(x-y)=0 и 2x-y=1

РешениеРешите систему уравнений (x+y)(x-y)=0 2x-y=1x² - y² = 0y = 2x - 1y = 2x - 1x² - (2x - 1)² = 0x² - 4x² + 4x - 1 = 0- 3x² + 4x - 1 = 03x² - 4x+ 1 = 0D = 16 - 4*3*1 =4x1 = (4 - 2)/6x1 =1/3x2 = (4 + 2)/6x2 =1x1 = 1/3y1 = 2*(1/3) - 1y1 = - 1/3x2 = 1y2 = 2*1 - 1y2 = 1Ответ: (1/3;- 1/3) ; (1; 1)