{х÷у×(х+у)=-4, х÷у+(х+у)=-3

Замена переменной  х÷у=u;  x+y=vРешаем систему[latex] left { {{uv}=-4 atop {u+v=-3}} ight. \ \ left { {{ucdot(-3-u)}=-4 atop {v=-3-u}} ight. \ \ left { {{u^2+3u-4=0 atop {v=-3-u}} ight. \ \ left { {{u_1=-4; u_2=1 atop {v_1=1;v_2=-4}} ight. [/latex]1)[latex] left { {{ frac{x}{y} =-4} atop {x+y=1}} ight. \ \ left { {{x=-4y} atop {-4y+y=1}} ight. \ \ left { {{y=- frac{1}{3} } atop {x= frac{4}{3} }} ight. [/latex]2)[latex] left { {{ frac{x}{y} =1} atop {x+y=-4}} ight. \ \ left { {{x=y} atop {2x=-4}} ight. \ \ left { {{y=-2} atop {x=-2}} ight. [/latex]