Решите неравенство log1/3 (12-x)<2

[latex]log_{1/3}(12-x) extless 2\OD3:\12-x extgreater 0\x extless 12\\log_{1/3}(12-x) extless log_{1/3} frac{1}{9}\0 extless frac{1}{3} extless 1\\12-x extgreater frac{1}{9} \\x extless 12- frac{1}{9}\\x extless 11 frac{8}{9}\\xin (-infty;11 frac{8}{9}) [/latex]