Правильно ли я решил? Помогите срочно!!! 5/b+2 - 1/b = 5b-b+2/b²+2 = 4b+2/b²+2 x²-3xy/x²-y² + y/x-y = x²-3xy=y(x-y)/x²-y² = x²-3xy+xy-y²/x²-y² = x²-2xy-y²/x²-y² /-дробная черта

[latex] frac{5}{b+2}- frac{1}{b}= frac{5*b-1*(b+2)}{(b+2)*b}= frac{5b-b-2}{(b+2)*b}= frac{4b-2}{b(b+2)} \ frac{x^2-3xy}{x^2-y^2}+ frac{y}{x-y}=frac{x^2-3xy}{(x-y)(x+y)}+ frac{y}{x-y}=frac{x^2-3xy+y(x+y)}{(x-y)(x+y)}=frac{x^2-3xy+xy+y^2}{(x-y)(x+y)}= \ =frac{x^2-2xy+y^2}{(x-y)(x+y)}=frac{(x-y)^2}{(x-y)(x+y)}= frac{x-y}{x+y} [/latex]