Помогите решить √3*sin x/2+1=cosx

√3*sin(x/2)+1=cosxcosx=cos(2*(x/2))=cos²(x/2)-sin²(x/2)=1-2sin²(x/2)√3*sin(x/2)+1=1-2sin²(x/2)2sin²(x/2)+√3*sin(x/2)=0sin(x/2)*(2sin(x/2)+√3)=0sin(x/2)=0 или 2sin(x/2)+√3=01. sin(x/2)=0 частный случай. x/2=π/2+2πn, n∉Z |*2x₁=π+4πn, n∈Z2. 2sin(x/2)+√3=0sin(x/2)=-√3/2x/2=(-1)^n *arcsin(-√3/2)+πn, n∈Zx/2=(-1)^(n+1) *(π/3)+πn, n∈Z |*2x₂=(-1)^(n+1) *(2π/3)+2πn, n∈Z