[latex]1+2sin frac{ pi x}{3}=0 [/latex] если х (2; 4)

1+2sin(πx/3)=02sin(πx/3)=-1sin(πx/3)=-1/2πx/3=(-1)^n *arcsin(-1/2)+πn, n∈Zπx/3=(-1)^(n+1) *(π/6)+πn, n∈Z |:(π/3)x=(-1)^(n+1) *(1/2)+3n, n∈Zn=0. x=(-1)¹ *(1/2)+3*0. x=1/2 ∉(2;4)n=1. x=(-1)²*(1/2)+3*1. x=3,5n=2. x=(-1)³ *(1/2)+3*2. x=5?5∉(2;4)ответ: х=3,5