(4х+1)(х+5)=(4х+1)(3х+2)

[latex](4x+1)(x+5)=(4x+1)(3x+2) |:(4x+1) \ x+5=3x+2 \ x-3x=2-5 \ -2x=-3 \ x=1.5[/latex]

4x²+20x+x+5=12x²+8x+3x+24x²-12x²+20x+x-8x-3x=2-5-8x²+10x=-3-8x²+10x+3=0D=b²-4ac=100-4*(-8)*3=100+96=4>0, 2 корняx₁=[latex] frac{-b+ sqrt{D} }{2a} = frac{-10+2}{-16}= frac{-8}{-16}= frac{1}{2}=0,5 [/latex]x₂=[latex] frac{-b- sqrt{D} }{2a}= frac{-10-2}{-16}= frac{-12}{-16}= frac{3}{4} = 0,75[/latex]Ответ: x₁=0,5, x₂=0,75