(3x-1)(x+3)=x(1-6x)  решите

[latex](3x-1)(x+3)=x(1-6x) \ 3x^2+9x-x-3=x-6x^2 \ 9x^2+7x-3=0 \ Delta=49+108=157 \ sqrt{Delta}= sqrt{157}=12,52 \ x_1= frac{-7-12,52}{18} = -frac{19,52}{18}=-1,08 \ x_2= frac{-7+12,52}{18}= frac{5,52}{18}=0,3 \ [/latex]

(3х-1)(х+3)=х(1-6х)3x²+9x-x-3=x-6x²9x²+7x-3=0D=b²-4ac=7²-4*9*(-3)=49+108=157x1=(-7+√157)/18x2=(-7-√157)/18