[latex]sin4x+sin^{2}2x=0[/latex]

sin 4x + sin^2 2x = 02sin 2x*cos 2x + sin^2 2x = 0sin 2x*(2cos 2x + sin 2x) = 01) sin 2x = 0; 2x = pi*k; x1 = pi/2*k2) 2cos 2x + sin 2x = 0sin 2x = -2cos 2xtg 2x = -22x = -arctg 2 + pi*n; x2 = -1/2*arctg 2 + pi/2*n

sin 4x + sin² 2x = 02sin 2x • cos 2x + sin² 2x = 0sin 2x • (2cos 2x + sin 2x) = 0sin 2x = 0; 2x = п • k; x1 = п/2 • k2cos 2x + sin 2x = 0sin 2x = - 2cos 2xtg 2x = - 22x = -arctg 2 + п • n; x2 = -1/2 • arctg 2 + п/2 • n