2y-2 / y+3 - 18 / [latex] y^{2} [/latex] - 9 =y-6 / y-3 помогите)))))))

[latex]frac{2y-2}{y+3}-frac{18}{y^2-9}=frac{y-6}{y-3}; ;; ; ; ODZ:; xe pm 3\\frac{2(y-1)}{y+3}-frac{18}{(y-3)(y+3)}-frac{y-6}{y-3}=0\\frac{2(y-1)(y-3)-18-(y-6)(y+3)}{(y-3)(y+3)}=0\\frac{2(y^2-4y+3)-18-(y^2-3y-18)}{(y-3)(y+3)}=0\\frac{y^2-5y+6}{(y-3)(y+3)}=0\\y^2-5y+6=0\\y_1=2,; ; y_2=3otin ODZ\\Otvet:; x=2[/latex]

[latex] frac{2y-2}{y+3} - frac{18}{y^{2} - 9} = frac{y-6}{y-3}[/latex][latex] frac{2y-2}{y+3} - frac{18}{(y-3)(y+3)} = frac{y-6}{y-3}[/latex]Приводим дроби к общему знаменателю.[latex]frac{(2y-2)(y-3)}{(y+3)(y-3)} - frac{18}{(y-3)(y+3)} - frac{(y-6)(y+3)}{(y-3)(y+3)}=0 \ \ [/latex][latex]frac{(2y-2)(y-3)-18-(y-6)(y+3)}{(y+3)(y-3)} =0 \ \ frac{2y ^{2} -2y-6y+6-18-y ^{2} +6y-3y+18}{(y+3)(y-3)} =0 \ \ frac{y ^{2} -5y+6}{(y+3)(y-3)} =0 \ \ left { {{y ^{2} -5y+6=0}atop {(y+3)(y-3) eq 0}} ight. left { {{y=2; y=3} atop {y eq 3; y eq -3}} ight. [/latex]Ответ. у=2