Помогите решить пожалуйста 1.( 5/x ) - (3/3-x) < 0 2. sin2x+((√3)/2)=0 

[latex]frac{5}{x}-frac{3}{3-x} extless 0\\frac{5(3-x)-3x}{x(3-x)} extless 0\\frac{15-5x-3x}{x(3-x)} extless 0\\frac{15-8x}{-x(x-3)} extless 0\\frac{-8(x-frac{15}{8})}{-x(x-3)} extless 0\\frac{8(x-frac{15}{8})}{x(x-3)} extless 0\\Znaki:; ; ---(0)+++(frac{15}{8})---(3)+++\\xin (-infty,0)U(frac{15}{8},3)[/latex][latex]2)sin2x=-frac{sqrt3}{2}\\2x=(-1)^{n}cdot (-frac{pi}{3})+pi n=(-1)^{n+1}cdot frac{pi}{3}+pi n,; nin Z\\x=(-1)^{n+1}cdot frac{pi}{6}+frac{pi n}{2},; nin Z[/latex]