8х-2у=у^2, если у=6х-1

[latex]egin{cases}y=6x-1\ 8x-2y=y^2end{cases}[/latex][latex]8x-2(6x-1)=(6x-1)^2 \ 8x-12x+2=36x^2-12x+1 \ -4x+2=36x^2-12x+1 \ 36x^2-8x-1=0 \ D=64-4*36*(-1)=64+144=208 \ x= frac{8б sqrt{208} }{72} = frac{8б sqrt{16*13} }{72} = frac{8б4 sqrt{13} }{72} = frac{4(2б sqrt{13} )}{72} = frac{2б sqrt{13} }{18}[/latex]Ответ:  [latex]frac{2б sqrt{13} }{18}[/latex]