Log₃(x-3)log₄(x-4) / x-5 [latex] leq [/latex] log₄(x-3)log₃(x-4)/ x-6 Помогите

[latex]frac{log_3(x-3)cdot log_4(x-4)}{x-5} leq frac{log_4(x-3)cdot log_3(x-4)}{x-6}\\ODZ:; left { {{x-3 extgreater 0,x-4 extgreater 0} atop {xe 5,xe 6}} ight. ; left { {{x extgreater 4} atop {xe 5,xe 6}} ight. \\frac{log_3(x-3)cdot frac{log_3(x-4)}{log_34}}{x-5}-frac{frac{log_3(x-3)}{log_34}cdot log_3(x-4)}{x-6} leq 0\\frac{log_3(x-3)cdot log_3(x-4)cdot (x-6-x+5)}{log_34cdot (x-5)(x-6)} leq 0\\log_34 extgreater 1 extgreater 0,; ; o ; ; frac{log_3(x-3)cdot log_3(x-4)}{(x-5)(x-6)} geq 0[/latex]Метод рационализации:[latex]log_{a}f; o (a-1)(f-1)\\frac{(3-1)cdot (x-3-1)(3-1)(x-4-1)}{(x-5)(x-6)} geq 0\\frac{(x-4)(x-5)}{(x-5)(x-6)} geq 0\\frac{x-4}{x-6} geq 0\\+++[4]---(6)+++\\xin (-infty,4]U(6,+infty)[/latex]С учётом ОДЗ:  [latex]xin (6,+infty)[/latex] .