Решите систему уравнений: 5x+6y=10 2x-3y=4

[latex] left { {{5x+6y=10} atop {2x-3y=4}} ight.[/latex]⇒[latex] left { {{5x+6y=10} atop {2(2x-3y)=2*4}} ight. [/latex]⇒[latex] left { {{5x+6y=10} atop {4x-6y=8}} ight. [/latex]⇒[latex] left { {{9x=18} atop {2x-3y=4}} ight. [/latex]⇒[latex] left { {{x=18:2=9} atop {2*2-3y=4}} ight. [/latex]⇒[latex] left { {{x=2} atop {4-3y=4}} ight. [/latex]⇒[latex] left { {{x=2} atop {4-4=3y}} ight. [/latex]⇒[latex] left { {{x=2} atop {0=3y}} ight. [/latex]⇒[latex] left { {{x=2} atop {y=0:3=0}} ight. [/latex]Ответ: ( х; у ) = ( 2; 0 ).