Сократи дробь 4x2−11x+6 ___________ x3−8.

[latex] frac{4x^2-11x+6}{x^3-8}=\\4x^2-11x+6=4(x-2)(x-0,75)\D=(-11)^2-4*4*6=121-96=25=5^2\x_1=(11+5)/(2*4)=16/8=2\x_2=(11-5)/(2*4)=6/8=0,75\\ frac{4x^2-11x+6}{x^3-8}= frac{4(x-2)(x-0,75)}{(x-2)(x^2+2x+4)}= frac{4(x-0,75)}{x^2+2x+4}[/latex]