Решите неравенство: а). [latex] log_{0,5} frac{x}{3} geq -2 [/latex] б). [latex] log_{0,6} (2x-1)< log_{0,6}x [/latex]

[latex]log_{0,5} frac{x}{3} geq -2, \  left { {{frac{x}{3}>0,} atop {frac{x}{3}leq 0,5^{-2};}} ight.  left { {x>0,} atop {xleq 12;}} ight. \ 00,} atop {x>0;}} ight. left { {{x>0,5,} atop {x>0;}} ight. x>0,5; \ 2x-1>x, \ left { {{x>0,5,} atop {x>1;}} ight. x>1; \ xin(1;+infty).[/latex]