Найдите значение дроби 1) x²-8x-33/10x+30 при x = -9;12;111

[latex] frac{x^2-8x-33}{10x+30} = frac{x(x-8)-33}{10(x+3)} [/latex]при x=-9 : [latex] frac{-9(-9-8)-33}{10(-9+3)} = frac{120}{60} =2[/latex]при x=12 [latex] frac{12(12-8)-33}{10(12+3)} = frac{15}{150} =0.1[/latex]при x=111 :[latex] frac{111(111-8)-33}{10(111+3)} = frac{11400}{1140} =10[/latex]