Вычислите6√7(arccos(√2/3))

[latex]6sqrt7cdot sin(arccosfrac{sqrt2}{3})=6sqrt7cdot frac{sqrt7}{3}=frac{6cdot 7}{3}=14\\\sin(arccosfrac{sqrt2}{3})=sin alpha ,; ; alpha =arccosfrac{sqrt2}{3},cosalpha=frac{sqrt2}{3}\\sin alpha =sqrt{1-cos^2 alpha }=sqrt{1-frac{2}{9}}=sqrt{frac{7}{9}}=frac{sqrt7}{3}[/latex]