Решите уравнение 3/х-8+8/х-3=2

[latex] frac{3}{x-8} + frac{8}{x-3} =2 \ \ frac{3(x-3)+8(x-8)}{(x-8)(x-3)} =2 \ \ frac{11x-73}{x^2-11x+24} =2 \ \ 11x-73=2(x^2-11x+24) \ 11x-73=2x^2-22x+48 \ 2x^2-33x+121=0 \ D=(-33)^2-4*2*121=1089-968=121 \ \ x_1= frac{33+11}{2*2} = frac{44}{4} =11 \ \ x_2= frac{33-11}{2*2} = frac{22}{4} = frac{11}{2} =5,5[/latex]