Решите систему уравнений: {4(x-2)-3(y+3)=1 {3(x+2)-2(x-y)=5

[latex] left { {{4(x-2)-3(y+3)=1} atop {3(x+2)-2(x-y)=5}} ight. left { {{4x-8-3y-9=1} atop {3x+6-2x+2y=5}} ight. left { {{4x-3y-17=1} atop {x+2y+6=5}} ight. left { {{4x-3y=1+17} atop {x+2y=5-6}} ight. \ left { {{4x-3y=18} atop {x+2y=-1}/*(-4)}ight. left { {{4x-3y=18} atop {-4x-8y=4}} ight. \ -11y=22 \ y=-2 \ 4x+6=18 \ 4x=12 \ x=3 \ \ left { {{y=-2} atop {x=3}} ight. [/latex]