Решить уравнение Tg^2(2x-Пи/6)=3

[latex]tg^2(2x-frac{pi}{6})=3\\tg^2(2x-frac{pi}{6})-(sqrt3)^2=0\\(tg(2x-frac{pi}{6})-sqrt3)(tg(2x-frac{pi}{6})+sqrt3)=0\\1.; tg(2x-frac{pi}{6})=sqrt3\\2x-frac{pi}{6}=frac{pi}{3}+pi n,\\2x=frac{pi}{2}+pi n,\\x=frac{pi}{4}+frac{pi n}{2},nin Z\\2.; tg(2x-frac{pi}{6})=-sqrt3\\[/latex][latex]2x-frac{pi}{6}=-frac{pi}{3}+pi k,\\x=-frac{pi}{12}+frac{pi k }{2},kin Z[/latex]