log²1/3x - log 1/3x = 2

ОДЗ  x > 0log 1/3x = t t^2 - t - 2=0D = -1^2 -4*1*-2 = 9t1 =1/2 (1-3)= -1; log 1/3x = -1; (1/3)^-1 = x ; x =3t2 =1/2 (1+3)=2 ; log 1/3x =2; (1/3)^2 = x; x =1/9ответ x = {1/9 ; 3}