Решить систему уравнений:№1у - 2х = 9х^2 + 2у = 14№24х - у + 1 = 0х^2 + ху + у^2 = 13№3х^2 - у^2 = -24х - у = 2

[latex]1)left { {{y-2x=9} atop {x^2+2y=14}} ight. left { {{y=9+2x} atop {x^2+2(9+2x)=14}} ight.\x^2+4x+4=0\D=0\x=-2;y=5 \2) left { {{4x-y+1=0} atop {x^2+xy+y^2=13}} ight. left { {{y=1+4x} atop {x^2+x(1+4x)+(1+4x)^2=13}} ight.\ 7x^2+3x-4=0\D=11^2\x_1=-1;x_2=- frac{4}{7} \y_1=-3;y_2=-1 frac{9}{7} \3) left { {{x-y=2} atop {x^2-y^2=-24}} ight. left { {{x=2+y} atop {(2+y)^2-y^2=-24}} ight. left { {{x=-5} atop {y=-7}} ight. [/latex]