(12y+18)(1.6-0.2y)=0

[latex]19.2y-2.4y^2-3.6y+28.8=0;\ D=b^2-4ac= 15,62-4*(-2,4)*28,8=243,36+276,48=519,84;\ x_1= frac{-15.6+22.8}{2*(-2.4)} =-1.5;\ x_2= frac{-15.6-22.8}{2*(-2.4)} =8 [/latex]

18у-2,4у^2+27-3,6у=02,4у^2-14,4у-27=0Д=36-4*1*(-27)=144, след 12у1=(6+12)/2=9у2=(6-12)/2=-3