Решите уравнение: 3x - 2√x - 8 = 0

[latex]3x - 2sqrt{x}-8 = 0\\ sqrt{x} = t\\ t > 0\\ 3t^2-2t-8 = 0\\ t_1t_2 = -frac{8}{3} = -frac{4}{3}*2\\ t_1+t_2 = frac{2}{3} = frac{6}{3} - frac{4}{3} = 2 - frac{4}{3}\\ t_1 = -frac{4}{3}\\ t_2 = 2\\ sqrt{x} = 2\\ fbox{x = 4}[/latex]