Решите уравнение 1) а+3а2= -11 2)х2-10х-39=0 3) 4у2-4у+1=0 4) –3t2-12t+6=0 5) 4а2+5= а

1) а+3а2= -11a+3*2a=-11a+6a=-117a=-11a=(-11)÷7a=-11÷72)х2-10х-39=02x-10x-39=0-8x-39=0-8x-39=0-8x=398x=-39x=(-39)÷8x=-39/83) 4у2-4у+1=04*2y-4y+1=08y-4y+1=04y+1=04y=-1y=(-1)÷4y=-1/44) –3t2-12t+6=0-3*2t-12t+6=0-6t-12t+6=0-18t+6=0-18t=-618t=6t=6÷18t=1/35) 4а2+5= а 4*2a+5=a8a+5=a8a+5=a8a+5=08a+5-a=07a+5=07a=-5a=(-5)÷7a=-5/7